Given:
The area is 30 square metres.
The length is 4m more than the width.
To find:
The width and length of the rectangle.
Explanation:
According to the question,
[tex]l=w+4[/tex]
Using the area of the rectangle is,
[tex]\begin{gathered} A=lw \\ 30=(w+4)w \\ 30=w^2+4w \\ w^2+4w=30 \\ w^2+4w+4=30+4 \\ (w+2)^2=34 \\ w+2=\sqrt{34} \\ w=\sqrt{34}-2 \\ w\approx5.83-2 \\ w\approx3.83m \end{gathered}[/tex]
So, the length would be,
[tex]\begin{gathered} l=3.83+4 \\ l=7.83m \end{gathered}[/tex]
Final answer:
• The length of the rectangle is 7.83m.
,
• The width of the rectangle is 3.83m.
