We have the next function
[tex]f(x)=e^2+\ln (9)[/tex]And we must calculate f'(x).
Since we have a sum
[tex]f^{\prime}(x)=\frac{d}{dx}e^2+\frac{d}{dx}\ln (9)[/tex]Knowing that the derivative of a constant function is zero and e^2, ln(9) are constants we obtain
[tex]\begin{gathered} f^{\prime}(x)=0+0=0 \\ \end{gathered}[/tex]ANSWER:
[tex]f^{\prime}(x)=0[/tex]