You have the following sentence:
51 times the difference between a number and 21 is equal to the number plus 58.
The previous expression can be written in an algebraic way as follow:
If z is the unknown number, you have:
[tex]51\cdot(z-21)=z+58[/tex]In order to solve the previous expression, proceed as follow:
- Expand parenthesis left side:
[tex]51z-1071=z+58[/tex]- Next, subtract z both sides and add 1071 both sides:
[tex]51z-z=58+1071[/tex]- Simplify like terms;
[tex]50z=1129[/tex]- Divide by 50 both sides:
[tex]z=\frac{1129}{50}\approx22.58[/tex]Hence, the value of z is 1129/50, or approximately 22.58
