Given:
[tex]\begin{gathered} FG=2\text{ ft} \\ BC=3\text{ ft} \\ \text{Area of a }\Delta ABC=18\text{ }sq\text{. ft} \end{gathered}[/tex]
Triangle EFG similar to triangle ABC
[tex]\begin{gathered} \frac{\text{Area of a }\Delta EFG}{Area\text{ of a }\Delta ABC}=\frac{FG^2}{BC^2} \\ \frac{\text{Area of a }\Delta EFG}{18}=\frac{2^2}{3^2} \\ \text{Area of a }\Delta EFG=\frac{4}{9}\times18 \\ \text{Area of a }\Delta EFG=8\text{ sq. ft} \end{gathered}[/tex]
