the Given data
The mass of the water is m = 2.35 kg
The initial temperature of water is T1 = 20oC
The final temperature of the water is T2 = 83oC
The expression for the heat energy required to warm up is given as:
[tex]q=mC(T_2-T_1)[/tex]The specific heat capacity of water is given as:
[tex]C=^{}4186J/kg^o\text{C}[/tex]Substitute the value in the above equation.
[tex]\begin{gathered} q=2.35\text{ kg}\times4186J/kg^o\text{C }\times(83^{\circ}C-20^{\circ}C) \\ q=619737.3\text{ J} \\ q=619737.3\text{ J}\times\frac{1\text{ kJ}}{1000\text{ J}} \\ q=619.737\text{ kJ} \end{gathered}[/tex]Thus, the amount of heat energy required to warm-up is 619.737 kJ.
