EXPLANATION:
We are given a field made up of a rectangle and two semi circles.
Please take note that two semi-circles with the same diameter can be joined together and we'll have a whole circle.
In other words, this field is made up of
(1) A rectangle
(2) A circle
The dimensions of both shapes are;
[tex]\begin{gathered} Rectangle: \\ l=84m,w=62m \end{gathered}[/tex][tex]\begin{gathered} Circle: \\ diameter=62m \\ radius=\frac{diameter}{2}=31m \end{gathered}[/tex]We shall now calculate the area of each after which we will add up our results;
[tex]\begin{gathered} Rectangle: \\ Area=l\times w \end{gathered}[/tex][tex]Area=84\times62[/tex][tex]Area=5208m^2[/tex][tex]\begin{gathered} Circle: \\ Area=\pi r^2 \end{gathered}[/tex][tex]Area=3.14\times31^2[/tex][tex]Area=3.14\times961[/tex][tex]Area=3017.54m^2[/tex]We have the area of the rectangular portion of the field, and that of both semi-circles (that is, area of the circle).
We now have the area of the entire field as follows;
[tex]Area=Rectangle+Circle[/tex][tex]Area=5208+3017.54[/tex][tex]Area=8225.54m^2[/tex]ANSWER:
[tex]Area=8,225.54m^2[/tex]