Respuesta :

Given the equation:

[tex]5\cdot\ln x=3.5[/tex]

Solve for x as follows:

[tex]\begin{gathered} \ln x=\frac{3.5}{5} \\ \\ \ln x=0.7 \\ \\ x=e^{0.7}\approx2.014 \end{gathered}[/tex]

Rounding to two decimals

So, the answer will be x = 2.01

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