What is the area of a sectorwhen 0 = 17/36 radians and r = 2?

To answer this question we will use the following formula to compute the area of a sector of radius r and central angle Θ:
[tex]Area=\frac{r^2\theta}{2}.[/tex]Substituting the given information we get:
[tex]Area=\frac{2^2*\frac{17\pi}{36}}{2}.[/tex]Simplifying the above result we get:
[tex]Area=\frac{4*\frac{17\pi}{36}}{2}=\frac{17\pi}{18}[/tex]Answer:
[tex]\frac{17\pi}{18}sq\text{ units.}[/tex]