Use the point slope of line equation y=mx+c to calculate the slope of the line.
[tex]\begin{gathered} y-5=6(x+\frac{1}{2}) \\ y-5=6x+3 \\ y=6x+8 \end{gathered}[/tex]
Here, the slope is 6 not -6.
Check whether the point (-1/2,5) is on the line.
[tex]\begin{gathered} 5=6(-\frac{1}{2})+8 \\ 5=-3+8 \\ 5=5 \end{gathered}[/tex]
Therefore, the point (-1/2,5) is on the line.
Compare the equation of the line y=6x+8 to that of y=mx+c implies,
c=8.
Here, the y intersept is 8 not 3.
