Explanation
remember the rule to subtract 2 fractions
[tex]\frac{a}{b}-\frac{c}{d}=\frac{ad-bc}{bd}[/tex]hence
[tex]1-\frac{1}{8}[/tex]* in cases of whole numbers let 1 as denominator,so
[tex]\frac{1}{1}-\frac{1}{8}[/tex]do the subtraction by following the rule
[tex]\begin{gathered} \frac{1}{1}-\frac{1}{8}=\frac{1*8-1*1}{1*8} \\ \frac{1}{1}-\frac{1}{8}=\frac{8-1}{8} \\ \frac{1}{1}-\frac{1}{8}=\frac{7}{8} \end{gathered}[/tex]Step 2
now,let
[tex]1=\frac{8}{8}[/tex]now,replace anddothe subtraction
[tex]\begin{gathered} \frac{8}{8}-\frac{1}{8} \\ \frac{8}{8}-\frac{1}{8}=\frac{8-1}{8}=\frac{7}{8} \end{gathered}[/tex]therefore, the answer is
[tex]\frac{7}{8}[/tex]I hope this helps you
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