To solve the given system, first, we multiply the first equation by -2.
[tex]\begin{cases}-2(-5x+1y)=-2\cdot29 \\ -10x+2y=58\end{cases}\to\begin{cases}10x-2y=-58 \\ -10x+2y=58\end{cases}[/tex]
Then, let's combine the equations.
[tex]\begin{gathered} 10x-10x+2y-2y=58-58 \\ 0=0 \end{gathered}[/tex]
As you can observe, the system doesn't have specific solutions, which means the system has infinitely many solutions because the given result is a true statement (0=0).
