Respuesta :
Given:
mass of the ball is
[tex]m=4\text{ kg}[/tex]The velocity of the ball is
[tex]v_1=14.8\text{ m/s}[/tex]The velocity of the ball after rebounds is
[tex]v_2=5.3\text{ m/s}[/tex]Required:
we have to calculate the change in momentum of the ball.
Explanation:
a ball moving with a certain velocity has a momentum P1 and after being hit by the bat, it has another momentum P2.
So , To calculate the change in momentum we will use formula
[tex]\Delta P=P_2-P_1.....(1)[/tex]we know the momentum is given as
[tex]P=mv[/tex]now equation (1) can be written as
[tex]\Delta P=mv_2-mv_1[/tex]plugging all the values in the above relation.we get
[tex]\begin{gathered} \Delta P=4\text{ kg}\times5.3\text{ m/s-4 kg}\times14.8\text{ m/s} \\ \Delta P=21.2-59.2\text{ kg m/s} \\ \Delta P=-38\text{ kg m/s} \end{gathered}[/tex]The negative sign shows that momentum has decreased.
Thus, the change in momentum of the ball is
[tex]\Delta P=38\text{ kg m/s}[/tex]