If we multiply the inequality n<4 by 3 we get the following:
[tex](n<4)\cdot3=3n<12[/tex]Now, on the next inequality we have the following:
[tex]\begin{gathered} 4m-3n<20 \\ \Rightarrow4m<20+3n \end{gathered}[/tex]By transitive property, we have:
[tex]\begin{gathered} 3n<12 \\ 4m<20+3n<20+12=32 \\ 4m<32 \\ \Rightarrow m<\frac{32}{4}=8 \\ m<8 \end{gathered}[/tex]therefore, the solution set for m is m<8
