The annual salaries of employees in a large companyare approximately normally distributed with a mean of$50,000 and a standard deviation of $20,000.a.What percent of people earn less than $40,000?b.What percent of people earn between $40,000 and $70,000?c.What percent of people earn more than $70,000?

Respuesta :

Let x be the normal variable denoting the annual salaries of employees

a) Probability of people earning less than $40,000 is given by:

[tex]P(x<40000)=P(z<\frac{40000-50000}{20000})[/tex]

then:

[tex]=P(z<\frac{-10000}{20000})=P(z<\frac{-1}{2})=P(z<-0.5)[/tex]

From z tables

[tex]=0.3085[/tex]

Thus, in percent 0.3085 x 100 = 30.85%

Answer: People earn less than $40,000 is 30.85%

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b) Probability of people earning between $40,000 and $70,000 is:

[tex]P(40000Then[tex]\begin{gathered} =P(\frac{-10000}{20000}From z tables[tex]=0.8413-0.3085=0.5328[/tex]

This is in percent 0.5328 x 100 = 53.28%

Answer: 53.28% of people earn between $40,0000 and $70,000

Graph

c) Probability of people earning more than $70,000 is:

[tex]P(x>70000)=1-P(z<\frac{70000-50000}{20000})[/tex]

Then

[tex]=1-P(z<\frac{20000}{20000})=1-P(z<1)[/tex]

From z tables

[tex]=1-0.8413=0.1587[/tex]

In percent is 0.1587 x 100 = 15.87%

Answer: The percent of people who earn more than $70,000 is 15.87%

Graph

Ver imagen FredL466247
Ver imagen FredL466247
Ver imagen FredL466247