Given
Write the vector v in terms of i and j whose magnitude | V || and direction 0 are given.
lvl = 34, 0 = 135°
v=
Solution
[tex]\begin{gathered} x=34\sin 135 \\ x=24.0416\text{ } \\ x=17\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} y=34\cos \text{ 135} \\ y=-24.0416 \\ y=-17\sqrt[]{2} \end{gathered}[/tex]The final answer
[tex]v=(17\sqrt[]{2}i,\text{ -17}\sqrt[]{2}j)\text{ }[/tex]
