Respuesta :

[tex]\begin{gathered} So,\text{ the angle }\angle Q=\angle R \\ 2x+38=180^{\circ} \\ 2x=142^{\circ} \\ x=71^{\circ} \\ So,\text{ the exterior anle at Q is } \\ \Rightarrow180^{}-71^{\circ} \\ \Rightarrow109^{\circ} \end{gathered}[/tex]

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