The volume of the given sphere is 45 cubic units
[tex]\frac{4}{3}\pi\times r^3=45^{}[/tex]
Now replce r by 2r so that:-
[tex]\begin{gathered} \frac{4}{3}\pi\times(2r)^3=\frac{4}{3}\pi\times8\times r^3 \\ =8\times\frac{4}{3}\pi\times r^3 \\ =8\times45 \\ =360 \end{gathered}[/tex]
So the volume of the sphere twice the radius of first sphere is 360 cubic units.
Hence the correct option is (B).
