To solve this question, we need to know the molar mass of Mn and O. We can look for it at the periodic table:
Mn = 54.938044 g/mol
O = 15.999 g/mol
Now, we multiply each molar mass by the number of atoms of each element in the compound Mn3O4 and sum the result.
There are 3 atoms of Mn and 4 atoms of O.
So:
(3x54.938044) + (4x15.999) = 228.81 g/mol
Answer: 228.81 g/mol
