SOLUTION to question 8.
The area of the shaded portion is caculated by using the formula
[tex]\text{Area of external circle- Area of the internal circle}[/tex]
Hence
Area of the bigger circle will be obtain using the formula
[tex]\begin{gathered} \pi R^2 \\ \text{where} \\ \pi=3.14, \\ R=\frac{6}{2}=3 \end{gathered}[/tex]
substitute into the formula, we have
[tex]=3.14\times3^2=3.14\times9=28.26cm^2[/tex]
Hence
Area of the bigger circle is 28.26cm²
There area of the bigger circle will be
[tex]\begin{gathered} \pi r^2 \\ \text{where r=}\frac{\text{2}}{2}=1 \\ \\ 3.14\times1^2=3.14cm^2 \end{gathered}[/tex]
Hence
The ares of the internal circle is 3.14cm²
Hence
There area of the shaded portion is
[tex]28-26-3.14=25.12cm^2[/tex]
Therefore
The area of the of the shaded portion is 25.12cm²
