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STRUCTIONS: and the slope of the line denter it hereum=1/ INSTRUCTIONS: hind the slope of the line and enter it here: the vinerken of l'ind the y-intercept of the line u enter it here: Write the equation of the line in form y=mx+b rite the equation of e line in form y=mx tb y=1/2x +5 24

STRUCTIONS and the slope of the line denter it hereum1 INSTRUCTIONS hind the slope of the line and enter it here the vinerken of lind the yintercept of the line class=

Respuesta :

First, let's calculate the slope of the line.

To do so, we'll need two points that belong to the line. Taking a look at the graph, we can obtain points

[tex]\begin{gathered} (0,4) \\ \text{and} \\ (1,1) \end{gathered}[/tex]

This way, we'll get:

[tex]m=\frac{1-4}{1-0}\rightarrow m=-3[/tex]

Now, notice that point

[tex](0,4)[/tex]

is also the y-intercept of the line.

This way, the equation of the line in the slope-intercept form ( y = mx + b) is:

[tex]y=-3x+4[/tex]

Answers:

1. m = -3

2. y-intercept = 4

3. Equation: y = -3x + 4