To solve for x in the given equation;
[tex]6(3-3x)=4(3x-2)[/tex]Firstly, let's expand the brackets.
[tex]\begin{gathered} 6(3)-6(3x)=4(3x)-4(2) \\ 18-18x=12x-8 \end{gathered}[/tex]Then let's add 18x to both sides;
[tex]\begin{gathered} 18-18x+18x=12x+18x-8 \\ 18=30x-8 \end{gathered}[/tex]then add 8 to both sides;
[tex]\begin{gathered} 18+8=30x-8+8 \\ 26=30x \end{gathered}[/tex]then divide both sides by 30.
[tex]\begin{gathered} \frac{26}{30}=\frac{30x}{30} \\ \frac{26}{30}=x \\ x\text{ = }\frac{26}{30}=\frac{13}{15} \\ x=\frac{13}{15} \end{gathered}[/tex]The solution to the given equation is;
[tex]x=\frac{13}{15}[/tex]