To find the mean, we have to use the following formula
[tex]\bar{x}=\frac{\Sigma(x\cdot f)}{N}[/tex]
Where x represents each score and f represents the number of students. Using the given table, we have
[tex]\begin{gathered} \bar{x}=\frac{65\cdot8+70\cdot1+75\cdot2+80\cdot1+85\cdot1+90\cdot9+95\cdot4}{8+1+2+1+1+9+4} \\ \bar{x}=\frac{520+70+150+80+85+810+380}{26}=\frac{2095}{26} \\ \bar{x}\approx80.6 \end{gathered}[/tex]
Hence, the mean is 80.6, approximately.
