Answer:
[tex]J_c=8\frac{17}{32}ft[/tex]Explanation: Writing the statements into Mathematics gives the following result:
[tex]\begin{gathered} J_m=9\frac{3}{4}ft\Rightarrow(1) \\ J_c=\frac{7}{8}J_m\Rightarrow(2) \end{gathered}[/tex]Substituting the equation (1) into equation (2) gives the following answer:
[tex]\begin{gathered} J_c=\frac{7}{8}J_m\Rightarrow J_c=\frac{7}{8}\cdot9\frac{3}{4}ft=\frac{273}{32}ft \\ J_c=8\frac{17}{32}ft \end{gathered}[/tex]Conclusion: Chris Jumped 8 feet and (17/32)th of another foot.
