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A radioactive substance decays so that after t years, the amount remaining, expressed as a percent of the original amount, is A(t)=100(1.3)^-tDetermine the rate of decay after 10 years

Respuesta :

We have to use the following formula

[tex]\begin{gathered} A(t)=100(1.3)^{\text{ -}t} \\ A(100)=100(1.3)^{\text{ -10 }} \\ A(100)=\frac{100}{(1.3)^{10}}=\frac{100}{13.786}=7.254 \\ \\ \end{gathered}[/tex]

We had to use the formula given to you, so it will decay 7.254% per year.

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