We want to find which value must have x, so this equation is true:
[tex]14=\frac{(9x-8)}{2}[/tex]In order to solve the equation for x we want to "leave x alone" on one side of the equation.
In order to do that we just have to remember one simple rule: what we do on one side of the equal "=" is what we must do on the other side.
Step 1: taking 2 to the left side
[tex]\begin{gathered} 14=\frac{(9x-8)}{2} \\ \downarrow \\ 14\cdot2=9x-8 \\ 28=9x-8 \end{gathered}[/tex]Step 2: taking 8 to the left side
[tex]\begin{gathered} 28=9x-8 \\ \downarrow \\ 28+8=9x \\ 36=9x \end{gathered}[/tex]Step 3: taking 9 to the left side
[tex]\begin{gathered} 36=9x \\ \downarrow \\ \frac{36}{9}=x \\ 4=x \\ \end{gathered}[/tex]Then,
answer: x = 4
