Given an expression as below:
[tex]\frac{x-3}{x^2-6x+9}[/tex]
Using a partial fraction:
[tex]\frac{x-3}{x^2-6x+9}[/tex][tex]\frac{x-3}{x^2-6x+9}=\frac{A}{x-3}+\frac{B}{x-3}[/tex]
Where
[tex]x^2-6x+9=(x-3)^2=(x-3)(x-3)[/tex][tex]\begin{gathered} \frac{x-3}{(x-3)(x-3)} \\ \text{divide both side by x-3, cancel the common factor} \\ \frac{x-3}{(x-3)(x-3)}=\frac{1}{x-3} \end{gathered}[/tex]
Therefore the above expression = True
