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Find the second, fourth, and eleventh terms of sequence described by the rule.A(n) = 3 + (n - 1)(5)--------------------------------I already have:[tex]a(2) = 8[/tex][tex]a(4) = 18[/tex][tex]a(11) = ...[/tex]However now, I need to find A(11) = ?Please help me find A(11) =

Find the second fourth and eleventh terms of sequence described by the ruleAn 3 n 15I already havetexa2 8textexa4 18textexa11 texHowever now I need to find A11 class=

Respuesta :

Step 1

Given;

[tex]A(n)=3+(n-1)(5)[/tex]

Required; To find A(11)

Step 2

n= 11, Therefore, substitute 11 for n

[tex]\begin{gathered} A(11)=3+(11-1)(5) \\ A(11)=\text{ 3 + 10(5)} \end{gathered}[/tex][tex]\begin{gathered} A(11)=\text{ 3+50} \\ A(11)=53 \end{gathered}[/tex]

Hence, A(11) = 53

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