Given the equation:
[tex]b=x\mleft(y-3\mright)[/tex]Solve the equation for y:
[tex]\begin{gathered} b=x\mleft(y-3\mright)\rightarrow(\div x) \\ \frac{b}{x}=y-3\rightarrow(+3) \\ \frac{b}{x}+3=y-3+3 \\ \\ \frac{b}{x}+3=y \end{gathered}[/tex]So, the answer will be:
[tex]y=\frac{b}{x}+3[/tex]