As per given by the question,
There are given that the angle is 40 degrees and speed of 120 ft/h.
Now,
From the question,
here use the cosine rule,
Then,
cosine rule is,
[tex]s=\sqrt{(25)^2+(120)^2+2\times25\times120\cos(40)^{}}[/tex]Now,
[tex]\begin{gathered} s=\sqrt[]{625+14400+50\times120\times0.76_{}} \\ =\sqrt[]{15025+4560} \\ =\sqrt[]{19585} \\ =139.9 \\ =140 \end{gathered}[/tex]The resultant speed is 140 ft/h.
Hence, the option second is correct.