Find the perimeter of the triangle whose vertices (-2,-2), (4,-2), and (4,6) write the exact answer. Do not round

Given:
The vertices of the triangle: (-2,-2), (4,-2), and (4,6)
To find:
the perimeter of the triangle
To determine the perimeter, we will plot the points on the triangle:
We have two side lengths of the triangle. We need to get the 3rd side. Since the triangle is a right-angled triangle, we will apply Pythagoras's theorem to get the 3rd side
Hypotenuse² = opposite² + adjacent²
opposite = 8, adjacent = 6, hypotenuse = ?
[tex]\begin{gathered} hypotenuse^2\text{ = 8}^2\text{ + 6}^2 \\ hypotenuse^2\text{ = 64 + 36} \\ hypotenuse^2\text{ = 100} \\ hypotenuse\text{ = }\sqrt{100}\text{ = 10} \end{gathered}[/tex]The three sides are: 6, 8, 10
The perimeter of a triangle = sum of all 3 sides
[tex]\begin{gathered} The\text{ perimeter of the triangle = 6 + 8 + 10} \\ \\ The\text{ perimeter of the triangle = 24 } \end{gathered}[/tex]T