SOLUTION:
[tex]m\angle C=63^o,AB=28,AC=29,find\text{ }m\angle B[/tex]
A simple sketch will help;
We can use the sine rule to solve for the angle B;
[tex]\begin{gathered} \frac{28}{sin63}=\frac{29}{sinB} \\ \\ sinB=\frac{29sin63}{28} \\ \\ sinB=0.9228 \\ \\ B=67.34^o \end{gathered}[/tex]
Thus;
[tex]m\angle B=67.34^o[/tex]
