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A system of two equations is shown below:Equation C: a = 4b + 5Equation D: a = 6b − 2What value of a can be substituted into equation D to solve the system of equations? (5 points)4b + 56b − 24b6b

Respuesta :

Solution:

Given;

[tex]\begin{gathered} EquationC:a=4b+5 \\ \\ EquationD:a=6b-2 \end{gathered}[/tex]

Substitute the value of a in equation D to solve the system of equation;

[tex]\begin{gathered} 4b+5=6b-2 \\ \\ 2b=3 \\ \\ b=\frac{3}{2} \\ \\ a=4(\frac{3}{2})+5 \\ \\ a=11 \end{gathered}[/tex]

CORRECT ANSWER: 4b+5

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