1) According to the problem, each kiddie ride ticket costs 3 tokens. Therefore, for 5 kiddie rides, the total cost for one person is 3*5=15. However, if Akira is also on the kiddie ride the same five times, the total cost is 30
Thus, the inequality is
[tex]5t+3(10)\le50[/tex]
Solving for t,
[tex]\begin{gathered} \Rightarrow5t+30\le50 \\ \Rightarrow5t+30-30\le50-30 \\ \Rightarrow5t\le20 \\ \Rightarrow\frac{5t}{5}\le\frac{20}{5} \\ \Rightarrow t\le4 \end{gathered}[/tex]
Akira could go on 0, 1, 2, 3, or 4 thrill rides.
2) Let x be the number of additional boxes; therefore, the inequality that models the problem is
[tex]750x+750\cdot18\le20000[/tex]
Solving for x,
[tex]\begin{gathered} \Rightarrow750x+13500\le20000 \\ \Rightarrow750x+13500-13500\le20000-13500 \\ \Rightarrow750x\le6500 \\ \Rightarrow\frac{750x}{750}\le\frac{6500}{750} \\ \Rightarrow x\le\frac{26}{3} \\ \Rightarrow x\le8.6667 \end{gathered}[/tex]
Therefore, one can fit 8 extra boxes at most.
