the equation is:
[tex]27=1245+\frac{15x}{43}+x[/tex]so we can pass 1245 to the other side as "-1245" and sum the numbers with x, so 15/43+1=58/43
[tex]\begin{gathered} 27-1245=(\frac{15}{43}+1)x \\ -1218=\frac{58}{43}x \end{gathered}[/tex]and finally, we can pass the 43 multiplying and the 58 dividings:
[tex]-1218\cdot\frac{43}{58}=x=-903[/tex]So the answer is:
x=-903
