In the given triangles,
[tex]\begin{gathered} AC\parallel BD \\ \frac{AC}{BD}=\frac{60}{42}=\frac{10}{7}\ldots\text{.}(1) \\ \frac{AB}{BE}=\frac{40}{28}=\frac{10}{7}\ldots\text{.}\mathrm{}(2) \end{gathered}[/tex]
Also,
[tex]\angle CAB=\angle DBE\text{ (corresponding angles)}\ldots\ldots(3)[/tex]
Hence using equation (1), (2) and (3), the two triangles are similar from SAS property.
Thus, option (C) is correct.
