Given:
[tex]\text{length(l)}=9025\text{ in ; width(w)=36 in}[/tex][tex]\begin{gathered} \text{Perimeter of a rectangle=2(l+w)} \\ \text{Perimeter of a rectangle=}2(9025+36) \\ \text{Perimeter of a rectangle=}2(9061) \\ \text{Perimeter of a rectangle=}18122\text{ in.} \end{gathered}[/tex][tex]\begin{gathered} \text{Area of a rectangle=l}\times w \\ \text{Area of a rectangle=}9025\times36 \\ \text{Area of a rectangle=}324900in^2 \end{gathered}[/tex]