Calculate the object’s acceleration between 10.0s and 30.0s. (use the graph and the set of values to help you)


In order to find the acceleration of the object, use the following expression:
[tex]a=\frac{v_2-v_1}{t_2-t_1}[/tex]where v1 is the speed of the object at time t1 and v2 the speed at time t2.
In this case, based ont the given graph, you have:
t1 = 10.0s
t2 = 30.0s
v1 = 1m/s
v2 = 0m/s
replace the previous values into the formula for a and simplify:
[tex]a=\frac{0\frac{m}{s}-1\frac{m}{s}}{30.0s-10.0s}=0.05\frac{m}{s^2}[/tex]Hence, the acceleration between the given time interval is 0.05m/s^2