We will have the following:
We will have that the electrostatic force:
[tex]EF=\frac{kc_1c_2}{d^2}[/tex]Now, for all SI units we will have that the constant is almost exactly 9*19^9 m/farad; so the force on each mass will be:
[tex]\begin{gathered} (9\ast10^9)(1\ast10^{-6})(1\ast10^{-6})/(1.494)^2=\frac{1}{166}N \\ \\ \approx6.02\ast10^{-3}N \end{gathered}[/tex]Now, we find the acceleration; that is:
[tex]\begin{gathered} \frac{1}{166}N=(0.476kg)\alpha\Rightarrow\alpha=\frac{125}{9877}m/s^2 \\ \\ \Rightarrow\alpha\approx0.0127m/s^2 \end{gathered}[/tex]Now, we will have that if both charges have opposite signs then the acceleration of ach mass is approximately 0.0127 m/s^2 in the direction toward the other.
If both charges have the same sign, then the acceleration will be approximately 0.0127m/s^2 in the direction away from the other.
