To check if x is a solution to the equation, you have to replace the value of x into the equation and corroborate if both sides of the equal sign coincide.
[tex]\begin{gathered} \frac{1}{8}(x+56)=10 \\ \frac{1}{8}(24+56)=10 \\ \frac{1}{8}(80)=10 \\ 10=10 \end{gathered}[/tex]then, x = 24 is a solution
