In 2010 , the world's largest pumpkin weighed 1,210 kilograms. An average-sized pumpkin weighs 5,000grams.The 2010 world-record pumpkin weighs ________ kilograms more than an average-sized pumpkin. (Write your answer as a numeral.)The solution is _____________

Respuesta :

The world's largest pumpkin weighed:

[tex]W_{\text{Big}}=1,810Kg[/tex]

While an average-sized is:

[tex]W_{\text{avarage}}=5,000g[/tex]

First, we must have both in the same unit of measurement. But we already know that 1kg = 1,000g. For this reason, we can rewrite:

[tex]W_{\text{average}}=5\operatorname{kg}[/tex]

To know how much the big pumpkin weighs more than the averaged-sized, we just need to subtract the averaged-sized from the Big pumpking weigh.

[tex]\text{Difference}=W_{\text{Big}}-W_{\text{average}}=1,810-5=1,805\operatorname{kg}[/tex]

The 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

The solution is:

1805 kg