The amount of carbon dioxide is given by the following function:
[tex]f(t)=0.02*t^2+0.5[/tex]
The rate of production of carbon dioxide is going to be:
[tex]\frac{d(f(t))}{dt}=\frac{d}{dt}(0.02t^2+0.5)[/tex][tex]\frac{df(t)}{dt}=2*0.02*t^{2-1}+0[/tex]
Replacing t=2.
[tex]\begin{gathered} \frac{df(t)}{dt}=2*0.02*t^1 \\ \frac{df(2)}{dt}=2\times0.02*(2)^1=0.08 \end{gathered}[/tex]
Answer: The rate of production of carbon dioxide after two seconds is
C) 0.08mol/s.
