Answer:
Explanations:
According to the Gay's Lussac's law, the pressure of a given mass of gas is directly proportional to the temperature provided that the volume is constant. Mathematically;
[tex]\begin{gathered} P\alpha T \\ P=kT \\ k=\frac{P_1}{T_1}=\frac{P_2}{T_2} \end{gathered}[/tex]Given the following parameters
Initial pressure P1 = 11.5atm
Final pressure P2 = 3.3atm
Initial temperature T1 = 446.5K
Required
Final temperature T2
Substitute the given parameters into the formula
[tex]\begin{gathered} T_2=\frac{P_2T_1}{P_1} \\ T_2=\frac{3.3\times446.5}{11.5} \\ T_2=128.13K \end{gathered}[/tex]Hence the final temperature in kelvins is 128.13K
