To convert both units we need to find the ratio between the weight units and the volume units. We want to do the following product
[tex]\frac{kg}{m^3}\times\frac{lb}{kg}\times\frac{m^3}{ft^3}=\frac{lb}{ft^3}[/tex]To find the corresponding ratios, we're going to use the following conversions
[tex]\begin{gathered} 1kg=2.2lb \\ 1m^3=35.3ft^3 \end{gathered}[/tex]Then, rewritting those conversions as the desired ratios, we have
[tex]\begin{gathered} 1kg=2.2lb\implies\frac{2.2lb}{1kg}=1 \\ 1m^3=35.3ft^3\implies\frac{1m^3}{35.3ft^3}=1 \end{gathered}[/tex]If we substitute those ratios on the first equation using the given densi,y value we're going to have our answer.
[tex]\frac{2350kg}{1m^3}\times\frac{2.2lb}{1kg}\times\frac{1m^3}{35.3ft^3}=146.46\frac{lb}{ft^3}[/tex]