The intersection of two secants has the following relation:
[tex]a\times b=c\times d[/tex]
Using the given information, we have.
[tex]12\times(x+12)=18\times(16+18)[/tex]
Now, we solve for x.
[tex]\begin{gathered} 12x+144=18\times34 \\ 12x=612-144 \\ 12x=468 \\ x=\frac{468}{12} \\ x=39 \end{gathered}[/tex]
Hence, x is equal to 39.
