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Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B^2 to both sides of the equation in step 4, what is the constant on the right side of the equation? a. -32b. 112c. 160

Respuesta :

1. Write the equation in the form:

[tex]Ax^2+Bx+C=0[/tex]

[tex]2x^2+8x-12=0[/tex]

You indentify A is 2 and B is 8 in the given equation:

[tex]A=2[/tex][tex]B=8[/tex]

2. 4A is 8 (4*2=8):

[tex]8\lbrack2x^2+8x-12\rbrack=8\lbrack0\rbrack[/tex]

[tex]16x^2+64x-96=0[/tex]

3.

[tex]16x^2+64x=96[/tex]

4. B^2 is 64 (8*8=64)

[tex]\lbrack16x^2+64x\rbrack+64=\lbrack96\rbrack+64[/tex][tex]16x^2+64x+64=160[/tex]After step 4, the constant on the right side of the equation is 160

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