find the zero(s) of the following function
f(v)=v^2+9v+20
Remember that the zeros of the function are the values of v when the function f(v) is equal to zero
so
v^2+9v+20=0
Applying the quadratic formula
a=1
b=9
c=20
substitute
[tex]v=\frac{-9\pm\sqrt[]{9^2-4(1)(20)}}{2(1)}[/tex][tex]\begin{gathered} v=\frac{-9\pm\sqrt[]{1}}{2} \\ \\ v=\frac{-9\pm1}{2} \\ \\ v_1=-4 \\ v_2=-5 \end{gathered}[/tex]the zeros are
v=-4 and v=-5
