Given data:
The first side given is FG =17.
The second given side is HF=20.
The expression for the Pythagoras theorem is,
[tex]\begin{gathered} (HF)^2=(FG)^2+(GH)^2 \\ (20)^2=(17)^2++(GH)^2 \\ GH^2=111 \\ GH=10.5 \end{gathered}[/tex]
The angle F is,
[tex]\begin{gathered} \cos (m\angle F)=\frac{FG}{HF} \\ =\frac{17}{20} \\ m\angle F=31.8^{\circ} \end{gathered}[/tex]
The angle H is,
[tex]\begin{gathered} m\angle H+m\angle F+m\angle G=180^{\circ} \\ m\angle H+31.8^{\circ}+90^{\circ}=180^{\circ} \\ m\angle H=58.2^{\circ} \end{gathered}[/tex]
Thus, the option (b) is correct.
