First, calculate the probability that a student chosen at random is a male that got an A
[tex]\begin{gathered} P(\text{male \mid A})=\frac{\text{number of male student who got an A}}{\text{total number of students}} \\ P(\text{male \mid A})=\frac{2}{43} \end{gathered}[/tex]Next, since we are looking for a student who is NOT a male that got an A, subtract from the total probability 1
[tex]\begin{gathered} P(\text{not male who got an A})=1-\frac{2}{43} \\ P(\text{not male who got an A})=\frac{43}{43}-\frac{2}{43} \\ P(\text{not male who got an A})=\frac{41}{43} \\ P(\text{not male who got an A})=0.953488 \end{gathered}[/tex]Rounding our answer to the nearest 3 decimal places, the probability that a student chosen at random is NOT a male that got an A is 0.953.
