Given:
[tex]\cos \theta=\frac{3}{5}[/tex]
adjacent side = 3 and hypotenuse=5
[tex](opposite)^2=(hypotenuse)^2-(adjacent)^2[/tex][tex](Opposite)^2=25-9[/tex][tex]\text{opposite}=4[/tex][tex]\tan \theta=\frac{Opposite}{\text{adjacent}}[/tex][tex]\tan \theta=\frac{4}{3}[/tex]
