We have to find the line that pass through points (-7,0) and (0,6).
The points given are the intercepts of the line, so the slope will be:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{6-0}{0-(-7)}=\frac{6}{7}[/tex]We then can write the slope-point equation as:
[tex]\begin{gathered} y-y_2=m(x-x_2) \\ y-6=\frac{6}{7}(x-0) \\ y=\frac{6}{7}x+6 \\ 7\cdot y=6x+6\cdot7 \\ 7y=6x+42 \\ 6x-7y+42=0 \end{gathered}[/tex]Answer: the equation in general form is 6x - 7y + 42 = 0
